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標題:

想問2條f.1 數學題 急..............

發問:

1. (u^8v^9)/(u^7v^2)X (uv^7) 2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4) 好急架,,聽日要交喇,,真係好難丫 幫幫手丫!! 更新: 冇所謂!!

最佳解答:

1. (u^8v^9)/(u^7v^2)X (uv^7) (u^8 v^9)/(u^7 v^2)X (u v^7) =u^(8-7+1) v^(9-2+7) =u^2 v^14 2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4) (-7a^3 b^2)X(-8b^4 c^5)/(-14a^2 b c^4) =-(7x8 / 14) a^(3-2) b^(2+4-1) c^(5-4) =-4a b^5 c

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此文章來自奇摩知識+如有不便請留言告知

1. (u^8v^9)/(u^7v^2)X (uv^7) =u^(8-7+1) v^(9-2+7) =u^2 v^14 2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4) =-(7x8 / 14) a^(3-2) b^(2+4-1) c^(5-4) =-4a b^5 c must correct~|||||1. (u^8v^9)/(u^7v^2)X (uv^7) = u^(8-7+1) v^(9-2+7) = u^2 v^14 2. (-7a^3b^2)X(-8b^4c^5)/(-14a^2bc^4) = [(-7)(-8)/(-14)][a^(3-2)b^(2+4-1)c^(5-4)] = -4ab^5c|||||乘定除先ar，唔該打清楚d