lgzrelv的部落格

標題:

幾條方程～請幫忙解答(急）

發問:

No.1: 2(6+p)+7p=3 p=? No.2:4[1510(m-1)]=80+25m m=? No.3: 90+8(s-5)=3(6+4s) THX~! 更新: sorry~!我打錯左！ No.2 should be:4[15+10(m-1)]=80+25m

最佳解答:

您好，我是 lop，高興能解答您的問題。 2(6+p)+7p=3 12 + 2p + 7p = 3 12 + 9p = 3 12 + 9p - 12 = 3 - 12 9p = -9 9p÷9 = -9÷9 p = -1 4[1510(m-1)]=80+25m 6040(m-1) = 80 + 25m 6040m - 6040 = 80 + 25m 6040m - 6040 + 6040 = 80 + 25m + 6040 6040m = 6120 + 25m 6040m-25m = 6120+25m-25m 6015m = 6120 6015m÷6015 = 6120÷6015 m = 408/401 90+8(s-5)=3(6+4s) 90 + 8s - 40 = 18 + 12s 50 + 8s = 18 + 12s 50 + 8s - 18 = 18 + 12s - 18 32 + 8s = 12s 32 + 8s - 8s = 12s - 8s 32 = 4s 32÷4 = 4s÷4 8 = s s = 8 2011-09-30 19:56:36 補充： correction of 002 , 4[15+10(m-1)]=80+25m 4(15+10m-10) = 80 + 25m 60 + 40m - 40 = 80 + 25m 20 + 40m = 80 + 25m 20 + 40m - 25m = 80 + 25m - 25m 20 + 15m = 80 20 + 15m - 20 = 80 - 20 15m = 60 15m÷15 = 60÷15 m = 4

其他解答:

第一題:2(6+p)+7p=3 p=? 答:2(6+p)+7p=3 12+2p+7p=3 12+9p=3 9p=3-12 9p=9 p=1 第二題:4[15+10(m-1)]=80+25m 答:4[15+10(m-1)]=80+25m 4[15+10m-10]=80+25m 60+40m-40=80+25m 20m+40=80+25m 20m-25m=80-40 -5m=40 m=-8 第三題:90+8(s-5)=3(6+4s) 答:90+8(s-5)=3(6+4s) 90+8s-40=18+12s 50+8s=18+12s -4s=-32 s=8|||||2(6+p)+7p=3 12 + 2p + 7p = 3 12 + 9p = 3 12 + 9p - 12 = 3 - 12 9p = -9 9p÷9 = -9÷9 p = -1 4[1510(m-1)]=80+25m 6040(m-1) = 80 + 25m 6040m - 6040 = 80 + 25m 6040m - 6040 + 6040 = 80 + 25m + 6040 6040m = 6120 + 25m 6040m-25m = 6120+25m-25m 6015m = 6120 6015m÷6015 = 6120÷6015 m = 408/401 90+8(s-5)=3(6+4s) 90 + 8s - 40 = 18 + 12s 50 + 8s = 18 + 12s 50 + 8s - 18 = 18 + 12s - 18 32 + 8s = 12s 32 + 8s - 8s = 12s - 8s 32 = 4s 32÷4 = 4s÷4 8 = s s = 8|||||p=-1 ...........

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