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physics
發問:
1.A parallel beam of light from a He-Ne laser, with a wavelength of 644 nm, falls on two very narrow slits 0.050 mm apart. How far apart are the fringes in the center of the pattern on a screen 2.0 m away?2.When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is... 顯示更多 1.A parallel beam of light from a He-Ne laser, with a wavelength of 644 nm, falls on two very narrow slits 0.050 mm apart. How far apart are the fringes in the center of the pattern on a screen 2.0 m away? 2.When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is 9.60 cm wide on a screen that is 2.53 m away. How wide is the slit? 3.A 3200 line/cm grating produces a third-order fringe at a 23.5° angle. What wavelength of light is being used?
最佳解答:
(1) This is a Young's double slit experiment with: a (slit separation) = 5 × 10-5 m λ (wavelength) = 644 × 10-9 m D (slit-screen distance) = 2 m So by the equation s = Dλ/a, where s is the fringe separation, we have: s = 2 × 644 × 10-9 / 5 × 10-5 = 0.02576 m or 2.576 cm (2) First of all, we have to find out the how wide the angle central diffraction peaks subtends at the slit: sin θ = 9.6 / (2 × 253) (dividing by 2 is because of there are 2 sides for the maximum) θ = 1.09° So we can predict that the first minimum angle occurs at 1.09°. Now, sub n = 1 for the equation dsin(θmin) = nλ, we can obtain d, the width of slit, being equal to: d = λ/sin(θmin) = 2.19 × 10-5 m (3) First of all, grating line spacing = 1/3200 = 3.125 × 10-4 cm or 3.125 × 10-6 m So using the equation for grating spacing diffraction: nλ = s sin θ where s = grating line spacing n = no. of order. So put n = 3, we have: 3λ = 3.125 × 10-6 × sin 23.5° λ = 415.4 nm
physics
發問:
1.A parallel beam of light from a He-Ne laser, with a wavelength of 644 nm, falls on two very narrow slits 0.050 mm apart. How far apart are the fringes in the center of the pattern on a screen 2.0 m away?2.When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is... 顯示更多 1.A parallel beam of light from a He-Ne laser, with a wavelength of 644 nm, falls on two very narrow slits 0.050 mm apart. How far apart are the fringes in the center of the pattern on a screen 2.0 m away? 2.When violet light of wavelength 415 nm falls on a single slit, it creates a central diffraction peak that is 9.60 cm wide on a screen that is 2.53 m away. How wide is the slit? 3.A 3200 line/cm grating produces a third-order fringe at a 23.5° angle. What wavelength of light is being used?
最佳解答:
(1) This is a Young's double slit experiment with: a (slit separation) = 5 × 10-5 m λ (wavelength) = 644 × 10-9 m D (slit-screen distance) = 2 m So by the equation s = Dλ/a, where s is the fringe separation, we have: s = 2 × 644 × 10-9 / 5 × 10-5 = 0.02576 m or 2.576 cm (2) First of all, we have to find out the how wide the angle central diffraction peaks subtends at the slit: sin θ = 9.6 / (2 × 253) (dividing by 2 is because of there are 2 sides for the maximum) θ = 1.09° So we can predict that the first minimum angle occurs at 1.09°. Now, sub n = 1 for the equation dsin(θmin) = nλ, we can obtain d, the width of slit, being equal to: d = λ/sin(θmin) = 2.19 × 10-5 m (3) First of all, grating line spacing = 1/3200 = 3.125 × 10-4 cm or 3.125 × 10-6 m So using the equation for grating spacing diffraction: nλ = s sin θ where s = grating line spacing n = no. of order. So put n = 3, we have: 3λ = 3.125 × 10-6 × sin 23.5° λ = 415.4 nm
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